x=input('enter how close you want to get to e with (1+1/n)^n')
u=exp(1);
count=0;
y=1;
while (abs(y-u)>=x)
    count=count +1;
    %y=sum from 0 to count of 1/(n!)
    sumo=0;
    for ii = 0:count
        sumo=sumo+(1/factorial(ii));
    end
    y=sumo;
end
fprintf('we needed %d computations to get within %f of e\n',count,x)