
Juli Rainbolt: answer to exercise 8.4? Joanne Redden: phi(n) Dorothy Zeiser: phi(n0 Steve Hennagin: phi(n), what else? Juli Rainbolt: Juli Rainbolt: 9.3 and 9.4 answers? Kathryn Weld has joined this chat. Steve Hennagin: m^2 congruent to m mod n Donna Nonnenkamp: rtsp://165.134.240.35/video0630pm1.sdp Russell Blyth: Yes Donna Nonnenkamp: vnc is the same as this morning Russell Blyth: need f(xy) = f(x)f(y) Donna Nonnenkamp: 165.134.131.41 Russell Blyth: QT problems? Blake Boursaw has joined this chat. Donna Nonnenkamp: Blake HI rtsp://165.134.240.35/ video0630pm1.sdp Donna Nonnenkamp: for quicktime Donna Nonnenkamp: vnc is the same as this morning Donna Nonnenkamp: 165.134.131.41 Michael Engquist has joined this chat. Blake Boursaw: got it, thx Russell Blyth: QT and VNC are up Donna Nonnenkamp: Michael hi Donna Nonnenkamp: rtsp://165.134.240.35/video0630pm1.sdp Michael Engquist: Hi, please give me id's Donna Nonnenkamp: for quicktime Russell Blyth: VNC the same Donna Nonnenkamp: vnc is the same as this morning Donna Nonnenkamp: 165.134.131.41 2:35 PM Russell Blyth: www.central.edu/algebraresources 2:45 PM Susan Pustejovsky has joined this chat. Russell Blyth: QT and VNC are up Donna Nonnenkamp: Hi Susan Donna Nonnenkamp: rtsp://165.134.240.35/video0630pm1.sdp Russell Blyth: VNC 165.134.131.41 Russell Blyth: as this morning Steve Hennagin: isn't this Euler's theorem? Russell Blyth: Yes 2:50 PM Russell Blyth: Q's? 2:55 PM Steve Hennagin: all either 1 or -1 Russell Blyth: Juli Rainbolt: yes 1,0,-1 Steve Hennagin: no 2 for 106, which is next? Blake Boursaw: I tried t^1000 -1 Blake Boursaw: It gave up Steve Hennagin: it is a great problem: I have friend who will enjoy this question 3:00 PM Blake Boursaw: How do you increase "permitted memory" if you really want to do long calculations? Joanne Redden: Bob has always dealt with that. Nora Strasser has left this chat. Steve Hennagin: you can also change the amount of memory in the start-up script/batch file Michael Engquist: Are you going to talk about any of the GAP packages? 3:05 PM Russell Blyth: switching tapes Donna Nonnenkamp: WE are changing tapes Juli Rainbolt: shut down quicktime - keep our fingers crossed Juli Rainbolt: pm2.sdp Steve Hennagin: just checked the gap.bat file: it has a switch -m 14m which might be the memory size (for windows) Juli Rainbolt: Starting QT again Juli Rainbolt: Steve - that's likely Steve Hennagin: change the 14m to whatever you want and restart gap Nikolaus Vonessen: qt works for me. Donna Nonnenkamp: rtsp://165.134.240.35/video0630pm2.sdp is the new URL for QT Blake Boursaw: Thanks Steve Juli Rainbolt: OK, I waved Donna Nonnenkamp: pm2 not pm1 Steve Hennagin: you are coming loud and clear Juli Rainbolt: Any probs? Kathryn Weld: All is fine. 3:10 PM Nikolaus Vonessen has left this chat. Nikolaus Vonessen has joined this chat. Donna Nonnenkamp: Nikolaus is everything working ok? Nikolaus Vonessen: yes. I accidentally quit aim. Donna Nonnenkamp: good 3:15 PM Juli Rainbolt: Any questions? 3:20 PM Steve Hennagin: p^2+p+1 perhaps? 3:25 PM Russell Blyth: but why? Nikolaus Vonessen: (p^3-1)/(p-1) Madeleine Gregoire: Not hearing anything. Russell Blyth: batteries are fine Steve Hennagin: hearing Ok here Russell Blyth: madeleine - restart QT Donna Nonnenkamp: Madeline - let us know if you are still having problems hearing us Madeleine Gregoire: Back on Donna Nonnenkamp: good Russell Blyth: good 3:30 PM Robert Quinn has left this chat. Blake Boursaw: It's the same number as before because the "normal vector" map gives a one-to-one correspondence. Juli Rainbolt: Questions? 3:35 PM Robert Quinn went offline before accepting your invitation. 3:40 PM Robert Quinn has joined this chat. Russell Blyth: OK! Robert Quinn: thanks Donna Nonnenkamp: Hi Robert Donna Nonnenkamp: Is all working ok? Robert Quinn: yes, thank you 3:50 PM Russell Blyth: Are there questions, or open for discussion Nikolaus Vonessen: In 12.1, don't you want to compute the degree of the smallest field extension of GF(2) containing (Z(2^4))^m ? Juli Rainbolt: Z((2^4)^m) Robert Quinn: In AlgebraicExtension(GF(2), f), how do you know which root is being adjoined? Russell Blyth: It does not matter - they are algebraically euqivalent Russell Blyth: equivalent Robert Quinn: so it doesn't matter, adjoining one, gives you all of them in the field extension? Russell Blyth: Not nec. a splitting field 3:55 PM Robert Quinn: ok, thanks Steve Hennagin: how to find the factors of our f in the extension field? Nikolaus Vonessen: I have only intermittent sound. 4:00 PM Russell Blyth: Final Q's?Back to Home Page
This PREP workshop is made possible by the NSF grant DUE: 0341481